 # 13 Simple Electrical Wiring Residential Chapter 4 Answers Images

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Electrical Wiring Residential Chapter 4 Answers - Question five calculate the strength stored in a 2 hundred micro farad capacitor linked to a 200 volt deliver accurate answer: 4 joules recollect e = 0.5cu2 question 6 if 3 10 micro farad capacitors are linked in series, the price on every capacitor may be correct solution: the equal question 7 why are discharge resistors often related to huge capacitors correct solution: to soundly burn up the charge held for that reason lowering surprise danger query eight what's the components had to calculate the strength saved in an inductor? Accurate answer: e = zero.5li2 question nine on an ac mains deliver of 230volts, what is the minimal voltage price which capacitors have to be rated at? Accurate solution: 400 volts .

Question 10 to calculate capacitance, which of the subsequent formulas is proper v = q/c v = c/q q = v/c q = c/v query eleven if a present day of 12.5a flows for a time of 2 mins calculate the quantity of charge transferred a hundred and fifty volts 1500 farads 1500 coulombs nine.6 coulombs query 12 if a charge of 500 micro coulombs is stored in a 25 micro farad capacitor, what is going to the p.D. Across the plates be? 0.2 volts 20 volts 12500 milli volts 1250 milli volts query thirteen calculate the price if a 200 micro farad capacitor is conected to a 200 volts deliver zero.04 coulombs 0.4 coulombs 0.04 joules zero.4 joules query 14 calculate the equivalent capacitance of 3 capacitors when connected in collection. There values are : five micro farad, 10 micro farad and 30 micro farad 2 micro farad zero.02 micro farad 0.33 micro farad 3 micro farad query 15 the electric area power of a capacitor is determined by way of the voltage among the plates divided via the thickness of the dialectric. But what devices are electric powered field electricity measured in ? Coulombs per square metre amps consistent with second volts according to metre watts consistent with 2nd question sixteen which is accurate formulation for calculating the electricity saved in a capacitor e = zero.5cu2 e = 0.5li2 c = w/0.5u u = w/zero.5c .